Comment faire pour supprimer une liste de tuple avec python?

Question

J'ai un tableau avec un drapeau pour chaque cas. Pour utiliser imprimer le tableau en HTML et utiliser colspan, je dois convertir ceci:

[{'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': True, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': True}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}, {'serve': False, 'open': False}] 

Dans ce pour le drapeau d'ouverture:

[{'colspan': 12, 'open': False}, {'colspan': 60, 'open': True}, {'colspan': 24, 'open': False}] 

Et un autre pour produire le servir un. Comment puis-je le faire de la manière la plus intelligente en utilisant Python?

Je pourrais compter le cas un par un, mais cela ne semble pas être une bonne idée.

Answer 1

def cluster(dicts, key): 
    current_value = None 
    current_span = 0 
    result = [] 

    for d in dicts: 
     value = d[key] 
     if current_value is None: 
      current_value = value 
     elif current_value != value: 
      result.append({'colspan': current_span, key: current_value}) 
      current_value = value 
      current_span = 0 
     current_span += 1 

    result.append({'colspan': current_span, key: current_value}) 
    return result 

by_open = cluster(data, 'open') 
by_serve = cluster(data, 'serve') 

La deuxième version, inspirée par Denis réponse et son utilisation de itertools.groupby:

import itertools 
import operator 

def make_spans(data, key): 
    groups = itertools.groupby(data, operator.itemgetter(key)) 
    return [{'colspan': len(list(items)), key: value} for value, items in groups] 

Answer 2

Ce ne voit pas clairement ce que vous avez besoin, mais j'espère que les exemples suivants vous aideront:

>>> groupped = itertools.groupby(your_list, operator.itemgetter('open')) 
>>> [{'colspan': len(list(group)), 'open': open} for open, group in groupped] 
[{'colspan': 12, 'open': False}, {'colspan': 60, 'open': True}, {'colspan': 78, 'open': False}] 
>>> groupped = itertools.groupby(your_list) 
>>> [dict(d, colspan=len(list(group))) for d, group in groupped] 
[{'serve': False, 'open': False, 'colspan': 12}, {'serve': True, 'open': True, 'colspan': 52}, {'serve': False, 'open': True, 'colspan': 8}, {'serve': False, 'open': False, 'colspan': 78}]