MySQL - Comment obtenir SUM d'un COUNT d'un champ?

Question

J'utilise l'instruction suivante et j'obtiens presque tout ce dont j'ai besoin. En outre, j'aimerais obtenir la somme de tous les résultats row_total.

SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
SUM(c.amount) as row_total 
FROM campaigns c 
JOIN campaign_codes cc 
LEFT JOIN partners p on p.id = 4 
WHERE c.partner_id = 4 AND cc.status = 0 AND c.id = cc.campaign_id 
GROUP BY c.id 
ORDER BY campaign_amount ASC 

Et voici un résultat d'exemple, la dernière colonne étant la colonne que je veux additionner:

1 10.00 30 992 24 9920.00 
    3 25.00 30 995 290 24875.00 
    16 50.00 30 988 335 49400.00 
    17 100.00 30 1000 335 100000.00 

Answer 1

Pour obtenir la somme en cours d'exécution:

SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
     COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
     SUM(c.amount) as row_total, @r := @r + SUM(c.amount) AS running_sum 
FROM (
     SELECT @r := 0 
     ) vars, 
     campaign c, … 

Pour obtenir le grand total (et tous les autres agrégats) comme un enregistrement supplémentaire:

SELECT * 
FROM (
     SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
       COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
       SUM(c.amount) as row_total 
     FROM campaign c, … 
     GROUP BY 
       c.id WITH ROLLUP 
     ) q 
ORDER BY 
     campaign_amount ASC 

Pour obtenir la somme totale dans un champ supplémentaire:

 SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
       COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
       SUM(c.amount) as row_total, 
       (
       SELECT SUM(c.amount) 
       FROM campaign c, … 
       -- the same but without the GROUP BY and ORDER BY clauses. 
       ) 
     FROM campaign c, … 
     GROUP BY 
       c.id 
     ORDER BY 
       campaign_amount ASC 

Answer 2

encapsulent votre requête comme:

SELECT SUM([row_total]) FROM (
Your query 
) Source 

D'après les commentaires ci-dessous, vous pourriez essayer ...

Your Query 
UNION ALL 
SELECT '', '', '', '', '', SUM([row_total]) FROM (
Your query 
) Source 

L'union vous permettra d'ajouter une ligne supplémentaire au jeu de résultats qui vous donnera une 'ligne totale'. Vous pouvez modifier les champs vides (les guillemets simples) pour qu'ils correspondent à vos types de données ou leur attribuer des valeurs spéciales qui représenteront votre ligne totale.

Answer 3

SELECT TB.campaign_id, TB.campaign_amount, TB.warning_trigger, TB.code_count, TB.days_remain, TB.row_total, SUM(TB.row_total) GlobalTotal FROM (SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
SUM(c.amount) as row_total 
FROM campaigns c 
JOIN campaign_codes cc 
LEFT JOIN partners p on p.id = 4 
WHERE c.partner_id = 4 AND cc.status = 0 AND c.id = cc.campaign_id 
GROUP BY c.id 
ORDER BY campaign_amount ASC) TB 
GROUP BY TB.campaign_id, TB.campaign_amount, TB.warning_trigger, TB.code_count, TB.days_remain, TB.row_total