Comment obtenir des caractères distincts de la colonne de chaîne dans mssql?

Question

Étant donné:

| name 
-+--------------------------- 
| Josef Knoller 
| Josef Somos 
| KFZ Wiesauer 

voulait résultat:

JOSEFKNMLRZWIAU 

(cas dans le résultat n'a pas d'importance - il était plus facile maintenant la touche UPPER alors que l'écriture)

Est-il possible de faites-le dans T-SQL?

---

désolé ... J'ai la colonne mixte et la ligne ... il est 1 colonne et n rangées

MLRZWIAU

• M vient de Somos
• L vient de Knoller
• R vient de Knoller
• ...

clearer?

Answer 1

DECLARE @result VARCHAR(MAX) 
SET @result = '' 

DECLARE @t TABLE(name VARCHAR(400)) 

INSERT INTO @t 
SELECT 'Josef Knoller' UNION ALL SELECT 'Josef Somos' UNION ALL SELECT 'KFZ Wiesauer' 

;WITH 
L0 AS (SELECT 1 AS c UNION ALL SELECT 1), 
L1 AS (SELECT 1 AS c FROM L0 A CROSS JOIN L0 B), 
L2 AS (SELECT 1 AS c FROM L1 A CROSS JOIN L1 B), 
L3 AS (SELECT 1 AS c FROM L2 A CROSS JOIN L2 B), 
L4 AS (SELECT 1 AS c FROM L3 A CROSS JOIN L3 B), 
Nums AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) AS i FROM L4), 
FilteredNums AS (SELECT i FROM Nums WHERE i<= 400), 
Letters AS(
SELECT UPPER(SUBSTRING(name,i,1)) AS L, ROW_NUMBER() OVER (ORDER BY name,i) AS RN 
FROM @t 
JOIN FilteredNums ON FilteredNums.i <= LEN(name)) 

SELECT @result = @result + L 
FROM Letters 
GROUP BY L 
ORDER BY MIN(RN) 

SELECT @result 

Answer 2

Ceci est un puzzle SQL assez commun. Vous aurez besoin d'une table Numbers, que je vais générer ici en utilisant un CTE (suppose SQL Server 2005 ou supérieur).

declare @Names table (
    name varchar(100) 
) 

insert into @Names 
    (name) 
    select 'Josef Knoller' union all 
    select 'Josef Somos' union all 
    select 'KFZ Wiesauer' 

;With Numbers As (
    Select Row_Number() Over (Order By c1.object_id) As Value 
    From sys.columns As c1 
     Cross Join sys.columns As c2 
) 
Select Distinct '' + case when Substring(nm.name, N.Value, 1)<>' ' then upper(Substring(nm.name, N.Value, 1)) else '' end 
    From Numbers N 
     Cross Join @Names nm 
    Where N.Value <= Len(nm.name) 
    For Xml Path('') 

Answer 3

DECLARE @result VARCHAR(MAX) 
SET @result = '' 

DECLARE @t TABLE(name VARCHAR(400)) 

INSERT INTO @t 
SELECT 'Josef Knoller' UNION ALL SELECT 'Josef Somos' UNION ALL SELECT 'KFZ Wiesauer' 

;with nums(i) as 
(
    select i=1 
    union all 
    select i=i+1 from nums where i < 400 
), 
Letters AS(
SELECT UPPER(SUBSTRING(name,i,1)) AS L, ROW_NUMBER() OVER (ORDER BY name,i) AS RN 
FROM @t JOIN nums ON nums.i <= LEN(name)) 

SELECT @result = @result + L 
FROM Letters 
GROUP BY L 
ORDER BY MIN(RN) 
OPTION (MAXRECURSION 400) 

SELECT @result