2010-08-12 18 views
1

Le prototype de embedRelation fait référence à un tableau 'options' (transmis sous la forme $ formArguments/$ formargs).Options de Symfony embedRelation - Définition de la visibilité du champ de sous-formulaire

Est-il possible de passer un tableau d'options:

embedRelation("Model","ModelForm",$options_arr); 

Lorsque le options_arr contient sous forme validateur/widgets/etc à définir pour la relation?

$formargs['something']['publish_date'] = new sfWidgetFormInputText(); 

Ou est-il possible de limiter les champs de formulaire affichés pour une relation de la sorte?

$formargs['something']['use_fields'] = array('publish_date'); 

De sfFormDoctrine.class.php ...

* Embed a Doctrine_Collection relationship in to a form 
* 
*  [php] 
*  $userForm = new UserForm($user); 
*  $userForm->embedRelation('Groups AS groups'); 
* 
* @param string $relationName The name of the relation and an optional alias 
* @param string $formClass  The name of the form class to use 
* @param array $formArguments Arguments to pass to the constructor (related object will be shifted onto the front) 
* @param string $innerDecorator A HTML decorator for each embedded form 
* @param string $decorator  A HTML decorator for the main embedded form 
* 
* @throws InvalidArgumentException If the relationship is not a collection 
*/ 
public function embedRelation($relationName, $formClass = null, $formArgs = array(), $innerDecorator = null, $decorator = null) 

...

Le plus proche que je suis en mesure d'obtenir une spécification pour le tableau formArgs $() est de sfFormPropel.class.php (j'utilise la doctrine 1.2):

* `title`: The title of the collection form once embedded. Defaults to the relation name. 
* `embedded_form_class`: The class name of the forms to embed. Uses the model name by default (a form based on a collection of Book objects embeds BookForm objects). 
* `collection_form_class`: Class of the collection form to return. Defaults to sfFormPropelCollection. 
* `hide_on_new`: If true, the relation form does not appear for new objects. Defaults to false. 
* `add_empty`: Whether to allow the user to add new objects to the collection. Defaults to true. 
* `add_delete`: Whether to add a delete widget for each object. Defaults to true. 
* `remove_fields`: The list of fields to remove from the embedded object forms 
* `item_pattern`: The pattern used to name each embedded form. Defaults to '%index%'. 

If `add_empty` is set to `true`, the following additional options are available: 

* `empty_label`: The label of the empty form. Defaults to 'new' + the relation name. 
* `add_link`: The text of the JavaScript link that displays the empty form. Defaults to `Ann new` 
* `max_additions`: The max number of additions accepted on the client side. Defaults to 0 (no limit) 

If `add_delete` is set to `true`, the following additional options are available: 

* `delete_name`: Name of the delete widget. Defaults to 'delete'. 
* `delete_widget`: Optional delete widget object. If left null, uses a `sfWidgetFormDelete` instance, which is a checkbox widget with a Javascript confirmation. 
* `alert_text`: The text of the Javascript alert to show. 
* `hide_parent`: Whether to hide the deleted form when clicking the checkbox. Defaults to true. 
* `parent_level`: The number of times parentNode must be called to reach the parent to hide. As a widget doesn't know if it's merged or embedded, this setting allows the JavaScript code used to hide the parent to find it. Recommended values: 6 for embedded form (default), 7 for merged form. 

Toute idée serait grandement appr eciated.

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Je pense que si vous mettez dire array('toto' => 'pwet') comme forme args, vous serez en mesure de récupérer « PWET » dans votre formulaire en utilisant $this->getOption('toto'); A partir de là tout est possible (réglage des widgets et validateurs)

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@ user739436, ne modifiez pas les réponses d'autres personnes pour ajouter votre propre contenu. Ajoutez un commentaire, s'il s'agit d'un commentaire, ou suggérez des modifications s'il s'agit d'un changement d'exemple de code. –

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@the Tin Man: hein? Souhaitez-vous publier cet article ailleurs? – greg0ire

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Non. Il y avait une modification en attente sur votre réponse de user739436 qui aurait dû être un commentaire. –

0

Pourquoi ne pas vous aller d'une autre manière:

$o = $this->isNew() ? new Model() : $this->getObject()->getModel(); 
$model_form = new ModelForm($o); 

//now configure widgets and validators 
$model_form->setWidget('publish_date', new sfWidgetFormInputText()); 
$model_form->useFields(array('publish_date')); 

$this->embedForm('Model', $model_form);