Un problème avec l'utilisation Smarty & Mysql et Jquery

Question

J'ai un problème dans l'utilisation Samrtm Mysql et Jquery ou Ajax et si j'utilise un reloader auto div il affiche une erreur php .. ce sont mes fichiers: ACCEPTER. html (Template)

{literal} 
<script type="text/javascript"> 
var auto_refresh = setInterval(
function() 
{ 
$('#invite').load('accept.php').fadeIn("slow"); 
}, 1000); 
</script> 
{/literal} 
<div id="invite"> 
<fieldset> 
<legend>Invites</legend> 
{section name=ct loop=$invites} 
You have an invite {$sender.user}<br /> 
<a href="?action=accept_contest&sid={$invites[ct].sendid}">Accept</a> | <a href="?action=cancel_contest&sid={$invites[ct].sendid}">Cancel</a> 
{/section} 
</fieldset> 
</div> 

accept.php (fichier principal)

<?php 

$time = date("i:s",time("s")); 
$sql_select_invite = mysql_query("SELECT * FROM invite WHERE recid = '$_SESSION[id]' AND accept = '0' AND endtime > '$time'"); 

while($invite = mysql_fetch_array($sql_select_invite)){ 
$sender = mysql_fetch_array(mysql_query("SELECT * FROM member WHERE id = '$invite[sendid]'")); 
    $contest->assign("sender", $sender); 
    $invites[] = $invite; 
} 
$contest->assign("invites", $invites); 

?> 

et quand j'utilise la chose Jquery ou Ajax il montre cette erreur:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\somefo\accept.php on line 6

Fatal error: Call to a member function assign() on a non-object in C:\AppServ\www\somefo\accept.php on line 11

Je ne sais pas pourquoi il montre ce .. et j'espère que vous me répondez et quoi ou comment résoudre ce problème

Merci ..

Answer 1

Pour php:

<?php 

$sql = mysql_connect(......); // connect to your server 
if (!$sql) { 
    die('Can\'t connect to database'); 
} 

// select your database 
mysql_select_db('your_db', $sql) or die('Can\'t select database'); 

$time = date("i:s",time("s")); 
$sql_select_invite_query = "SELECT * FROM invite WHERE recid = '$_SESSION[id]' AND accept = '0' AND endtime > '$time'"; 

// print it if you want to see sql query to test it in phpmyadmin 
echo $sql_select_invite_query; 
// -------------------------------------------------------------- 

$sql_select_invite = mysql_query($sql_select_invite_query, $sql); 

if (!$sql_select_invite) { // check for error in query 
    die(mysql_error());  // and print it 
} 

$invites = array(); // don't forget to make an empty array 

while($invite = mysql_fetch_array($sql_select_invite, $sql)){ 
    // this place is not good, just make it as you do before, with checks 
    $sender = mysql_fetch_array(mysql_query("SELECT * FROM member WHERE id = '$invite[sendid]'")); 

    $contest->assign("sender", $sender); 
    $invites[] = $invite; 
} 
$contest->assign("invites", $invites); // in your case there is no $invite 
             // array cause mysql_fetch_array returned 
             // false and it is not defined before [while] 

?> 

JS à tester:

setInterval(function() { 
    $('#invite').load('accept.php', function() { 
    alert('loaded'); // it is to check content is loaded 
    }).fadeIn("slow"); 
}, 1000);