Apache commons ftp

Question

i utilisé CrossFTP pour créer un serveur FTP

quand je connecté en utilisant Firefox, il fonctionne bien.

mais en utilisant Apache commons, il renvoie une exception

import java.net.SocketException; 
import org.apache.commons.net.ftp.FTPClient; 
import java.io.IOException; 

public class FtpConnectDemo { 
    public static void main(String[] args) throws SocketException, IOException { 
    FTPClient client = new FTPClient(); 
    client.connect("ftp://192.168.1.150"); 
    boolean login = client.login("ehab01", "CD7IZW0O"); 

    if (login) { 
     System.out.println("Login success..."); 
     boolean logout = client.logout(); 
     if (logout) { 
     System.out.println("Logout from FTP server..."); 
     } 
    } else { 
     System.out.println("Login fail..."); 
    } 
    client.disconnect(); 
    } 
} 

---

Exception in thread "main" java.net.UnknownHostException: ftp://192.168.1.150 
     at java.net.Inet6AddressImpl.lookupAllHostAddr(Native Method) 
     at java.net.InetAddress$1.lookupAllHostAddr(InetAddress.java:849) 
     at java.net.InetAddress.getAddressFromNameService(InetAddress.java:1200) 
     at java.net.InetAddress.getAllByName0(InetAddress.java:1153) 
     at java.net.InetAddress.getAllByName(InetAddress.java:1083) 
     at java.net.InetAddress.getAllByName(InetAddress.java:1019) 
     at java.net.InetAddress.getByName(InetAddress.java:969) 
     at org.apache.commons.net.SocketClient.connect(SocketClient.java:184) 
     at org.apache.commons.net.SocketClient.connect(SocketClient.java:273) 
     at com.ftp.FtpConnectDemo.main(FtpConnectDemo.java:19) 

Answer 1

Votre argument nom d'hôte doit être juste 192.168.1.150, pas ftp://192.168.1.150.